Tugas · pemrosesan data sulit JavaScript ·

Range add, range sum

/**
 * @param {number[]} nums
 * @param {Array[]} ops
 * @returns {number[]}
 */
function range_add_sum(nums, ops)

range_add_sum([1, 2, 3, 4], [["sum", 0, 3], ["add", 1, 2, 10], ["sum", 0, 1], ["sum", 2, 3]])  // -> [10, 13, 17]
range_add_sum([5], [["add", 0, 0, -5], ["sum", 0, 0]])  // -> [0]

• #1Google Gemini 3.8 Flashselesai · 10 dari 10 pengujianrespons dalam 5.2 dtk · waktu eksekusi 544 md · $0.0032

  ✓	range_add_sum([1, 2, 3, 4], [["sum", 0, 3], ["add", 1, 2, 10], ["sum", 0, 1], ["sum", 2, 3]])diharapkan [10, 13, 17]	3 md
  ✓	range_add_sum([5], [["add", 0, 0, -5], ["sum", 0, 0]])diharapkan [0]	1 md

  ✓ 2 md✓ <1 md✓ 25 md✓ 2 md✓ 2 md✓ 1 md⏱ 360 md⏱ 147 md
  Kode

  /**
   * @param {number[]} nums
   * @param {Array[]} ops
   * @returns {number[]}
   */
  function range_add_sum(nums, ops) {
    const n = nums.length;
    if (n === 0) return [];
  
    // Binary Indexed Tree (Fenwick tree) with range updates and range queries
    // Maintains: A[i] = nums[i] initially, plus updates.
    // sum(0..i) = (sum(B1, i) * (i + 1)) - sum(B2, i)
    // To add v to [l, r]:
    // add(B1, l, v), add(B1, r + 1, -v)
    // add(B2, l, v * l), add(B2, r + 1, -v * (r + 1))
  
    const b1 = new Float64Array(n + 2);
    const b2 = new Float64Array(n + 2);
  
    function bitAdd(idx, v) {
      const vIdx = v * idx;
      for (let i = idx + 1; i <= n; i += i & -i) {
        b1[i] += v;
        b2[i] += vIdx;
      }
    }
  
    function rangeAdd(l, r, v) {
      bitAdd(l, v);
      // For r + 1:
      const idx2 = r + 1;
      const v2 = -v;
      const vIdx2 = v2 * idx2;
      for (let i = idx2 + 1; i <= n; i += i & -i) {
        b1[i] += v2;
        b2[i] += vIdx2;
      }
    }
  
    function prefixSum(idx) {
      if (idx < 0) return 0;
      let s1 = 0;
      let s2 = 0;
      for (let i = idx + 1; i > 0; i -= i & -i) {
        s1 += b1[i];
        s2 += b2[i];
      }
      return s1 * (idx + 1) - s2;
    }
  
    // Precompute initial prefix sums of nums to avoid N updates
    const pref = new Float64Array(n + 1);
    for (let i = 0; i < n; i++) {
      pref[i + 1] = pref[i] + nums[i];
    }
  
    const results = [];
    const len = ops.length;
    for (let i = 0; i < len; i++) {
      const op = ops[i];
      if (op[0] === 'add') {
        rangeAdd(op[1], op[2], op[3]);
      } else {
        const l = op[1];
        const r = op[2];
        const initialSum = pref[r + 1] - pref[l];
        const addedSum = prefixSum(r) - prefixSum(l - 1);
        results.push(initialSum + addedSum);
      }
    }
  
    return results;
  }

• #2DeepSeek V4.1 Flashselesai · 10 dari 10 pengujianrespons dalam 1.5 dtk · waktu eksekusi 1.3 dtk · $0.0005

  ✓	range_add_sum([1, 2, 3, 4], [["sum", 0, 3], ["add", 1, 2, 10], ["sum", 0, 1], ["sum", 2, 3]])diharapkan [10, 13, 17]	2 md
  ✓	range_add_sum([5], [["add", 0, 0, -5], ["sum", 0, 0]])diharapkan [0]	1 md

  ✓ <1 md✓ <1 md✓ <1 md✓ 1 md✓ 1 md✓ 2 md⏱ 727 md⏱ 578 md
  Kode

  function range_add_sum(nums, ops) {
    const n = nums.length;
    const size = 1 << Math.ceil(Math.log2(n || 1));
    const sum = new Float64Array(2 * size);
    const lazy = new Float64Array(2 * size);
  
    for (let i = 0; i < n; i++) sum[size + i] = nums[i];
    for (let i = size - 1; i > 0; i--) sum[i] = sum[2 * i] + sum[2 * i + 1];
  
    function apply(node, l, r, v) {
      sum[node] += v * (r - l + 1);
      lazy[node] += v;
    }
  
    function push(node, l, r) {
      const v = lazy[node];
      if (v !== 0) {
        const mid = (l + r) >> 1;
        apply(2 * node, l, mid, v);
        apply(2 * node + 1, mid + 1, r, v);
        lazy[node] = 0;
      }
    }
  
    function update(node, l, r, ql, qr, v) {
      if (ql > r || qr < l) return;
      if (ql <= l && r <= qr) {
        apply(node, l, r, v);
        return;
      }
      push(node, l, r);
      const mid = (l + r) >> 1;
      update(2 * node, l, mid, ql, qr, v);
      update(2 * node + 1, mid + 1, r, ql, qr, v);
      sum[node] = sum[2 * node] + sum[2 * node + 1];
    }
  
    function query(node, l, r, ql, qr) {
      if (ql > r || qr < l) return 0;
      if (ql <= l && r <= qr) return sum[node];
      push(node, l, r);
      const mid = (l + r) >> 1;
      return query(2 * node, l, mid, ql, qr) + query(2 * node + 1, mid + 1, r, ql, qr);
    }
  
    const res = [];
    for (let i = 0; i < ops.length; i++) {
      const op = ops[i];
      if (op[0] === "add") {
        update(1, 0, size - 1, op[1], op[2], op[3]);
      } else {
        res.push(query(1, 0, size - 1, op[1], op[2]));
      }
    }
    return res;
  }

• #3OpenAI GPT-6 Lunatidak selesai · 4 dari 10 pengujianrespons dalam 4.1 dtk · waktu eksekusi 1.9 dtk · $0.0003

  ✓	range_add_sum([1, 2, 3, 4], [["sum", 0, 3], ["add", 1, 2, 10], ["sum", 0, 1], ["sum", 2, 3]])diharapkan [10, 13, 17]	3 md
  ✗	range_add_sum([5], [["add", 0, 0, -5], ["sum", 0, 0]])diharapkan [0]hasil [-5]	<1 md

  ✓ <1 md✓ 3 md✗ jawaban salah✓ 1 md✗ jawaban salah✗ jawaban salah⏱ jawaban salah⏱ jawaban salah
  Kode

  function range_add_sum(nums, ops) {
    const n = nums.length;
    const size = Math.ceil(Math.sqrt(n));
    const blocks = Math.ceil(n / size);
    const sums = new Float64Array(blocks);
    const lazy = new Float64Array(blocks);
  
    for (let i = 0; i < n; i++) sums[Math.floor(i / size)] += nums[i];
  
    function prefix(end) {
      let total = 0;
      let i = 0;
      while (i <= end) {
        const b = Math.floor(i / size);
        const blockEnd = Math.min(n - 1, (b + 1) * size - 1);
        if (i === b * size && blockEnd <= end) {
          total += sums[b] + lazy[b] * (blockEnd - i + 1);
          i = blockEnd + 1;
        } else {
          total += nums[i] + lazy[b];
          i++;
        }
      }
      return total;
    }
  
    const result = [];
    for (const op of ops) {
      const l = op[1], r = op[2];
      if (op[0] === "sum") {
        result.push(prefix(r) - (l ? prefix(l - 1) : 0));
        continue;
      }
  
      const v = op[3];
      let i = l;
      while (i <= r) {
        const b = Math.floor(i / size);
        const blockEnd = Math.min(n - 1, (b + 1) * size - 1);
        if (i === b * size && blockEnd <= r) {
          sums[b] += v * (blockEnd - i + 1);
          lazy[b] += v;
          i = blockEnd + 1;
        } else {
          nums[i] += v;
          sums[b] += v;
          i++;
        }
      }
    }
    return result;
  }

  Percobaan kedua

  tidak selesai · 5 dari 10 pengujianrespons dalam 3.4 dtk · $0.0003

  Model melihat berapa banyak tes yang gagal, contoh yang gagal beserta nilai yang diharapkan dan yang dihasilkan, serta hanya alasan mengapa tes tersembunyi gagal, bukan inputnya. Tidak memengaruhi peringkat atau rating.

  ✓	range_add_sum([1, 2, 3, 4], [["sum", 0, 3], ["add", 1, 2, 10], ["sum", 0, 1], ["sum", 2, 3]])diharapkan [10, 13, 17]	2 md
  ✗	range_add_sum([5], [["add", 0, 0, -5], ["sum", 0, 0]])diharapkan [0]hasil [-5]	<1 md

  ✓ 2 md✓ 4 md✗ jawaban salah✓ <1 md✓ <1 md✗ jawaban salah⏱ jawaban salah⏱ jawaban salah

  Kode

  function range_add_sum(nums, ops) {
    const n = nums.length;
    const size = Math.max(1, Math.ceil(Math.sqrt(n)));
    const blocks = Math.ceil(n / size);
    const sums = new Float64Array(blocks);
    const lazy = new Float64Array(blocks);
  
    for (let i = 0; i < n; i++) sums[Math.floor(i / size)] += nums[i];
  
    function rangeSum(l, r) {
      let total = 0;
      let i = l;
      while (i <= r) {
        const b = Math.floor(i / size);
        const start = b * size;
        const end = Math.min(n - 1, start + size - 1);
        if (i === start && end <= r) {
          total += sums[b] + lazy[b] * (end - start + 1);
          i = end + 1;
        } else {
          total += nums[i] + lazy[b];
          i++;
        }
      }
      return total;
    }
  
    const result = [];
    for (const op of ops) {
      const l = op[1], r = op[2];
      if (op[0] === "sum") {
        result.push(rangeSum(l, r));
      } else {
        const v = op[3];
        let i = l;
        while (i <= r) {
          const b = Math.floor(i / size);
          const start = b * size;
          const end = Math.min(n - 1, start + size - 1);
          if (i === start && end <= r) {
            sums[b] += v * (end - start + 1);
            lazy[b] += v;
            i = end + 1;
          } else {
            nums[i] += v;
            sums[b] += v;
            i++;
          }
        }
      }
    }
    return result;
  }

• #4MoonshotAI Kimi K2.7 Codetidak selesai · 0 dari 10 pengujianrespons dalam 53 dtk · waktu eksekusi <1 md · $0.02

  SyntaxError: Unexpected token ';'

  ✗	range_add_sum([1, 2, 3, 4], [["sum", 0, 3], ["add", 1, 2, 10], ["sum", 0, 1], ["sum", 2, 3]])diharapkan [10, 13, 17]SyntaxError: Unexpected token ';'	—
  ✗	range_add_sum([5], [["add", 0, 0, -5], ["sum", 0, 0]])diharapkan [0]SyntaxError: Unexpected token ';'	—

  ✗ SyntaxError✗ SyntaxError✗ SyntaxError✗ SyntaxError✗ SyntaxError✗ SyntaxError⏱ SyntaxError⏱ SyntaxError
  Kode

  /**
   * @param {number[]} nums
   * @param {Array[]} ops
   * @returns {number[]}
   */
  function range_add_sum(nums, ops) {
      const n = nums.length;
      const ans = [];
      if (n === 0) return ans;
  
      const size = n + 5; // extra room for r+1 updates
      const b1 = new Array(size).fill(0);
      const b2 = new Array(size).fill(0);
  
      function add(bit, idx, val) {
          for (let i = idx; i < size; i += i & -i) {
              bit[i] += val;
          }
      }
  
      function sum(bit, idx) {
          let s = 0;
          for (let i = idx; i > 0; i -= i & -i) {
              s += bit[i];
          }
          return s;
      }
  
      function rangeAdd(l, r, v) {
          add(b1, l, v);
          add(b1, r + 1, -v);
          add(b2, l, v * (l - 1));
          add(b2, r + 1, -v * r);
      }
  
      function prefix(idx) {
          return sum(b1, idx) * idx - sum(b2, idx);
      }
  
      function rangeSum(l, r) {
          return prefix(r) - prefix(l - 1);
      }
  
      // initialize with the original array values
      for (let i =

  Percobaan kedua

  selesai · 10 dari 10 pengujianrespons dalam 16 dtk · $0.0035

  Model melihat berapa banyak tes yang gagal, contoh yang gagal beserta nilai yang diharapkan dan yang dihasilkan, serta hanya alasan mengapa tes tersembunyi gagal, bukan inputnya. Tidak memengaruhi peringkat atau rating.

  ✓	range_add_sum([1, 2, 3, 4], [["sum", 0, 3], ["add", 1, 2, 10], ["sum", 0, 1], ["sum", 2, 3]])diharapkan [10, 13, 17]	2 md
  ✓	range_add_sum([5], [["add", 0, 0, -5], ["sum", 0, 0]])diharapkan [0]	1 md

  ✓ 3 md✓ 2 md✓ 2 md✓ 2 md✓ <1 md✓ <1 md⏱ 359 md⏱ 455 md

  Kode

  /**
   * @param {number[]} nums
   * @param {Array[]} ops
   * @returns {number[]}
   */
  function range_add_sum(nums, ops) {
      const n = nums.length;
      const ans = [];
      if (n === 0) return ans;
  
      const size = n + 5;
      const b1 = new Array(size).fill(0);
      const b2 = new Array(size).fill(0);
  
      function add(bit, idx, val) {
          for (let i = idx; i < size; i += i & -i) {
              bit[i] += val;
          }
      }
  
      function sum(bit, idx) {
          let s = 0;
          for (let i = idx; i > 0; i -= i & -i) {
              s += bit[i];
          }
          return s;
      }
  
      function rangeAdd(l, r, v) {
          l++;
          r++;
          add(b1, l, v);
          add(b1, r + 1, -v);
          add(b2, l, v * (l - 1));
          add(b2, r + 1, -v * r);
      }
  
      function prefix(idx) {
          return sum(b1, idx) * idx - sum(b2, idx);
      }
  
      function rangeSum(l, r) {
          return prefix(r + 1) - prefix(l);
      }
  
      for (let i = 0; i < n; i++) {
          rangeAdd(i, i, nums[i]);
      }
  
      for (let i = 0; i < ops.length; i++) {
          const op = ops[i];
          if (op[0] === "add") {
              rangeAdd(op[1], op[2], op[3]);
          } else {
              ans.push(rangeSum(op[1], op[2]));
          }
      }
  
      return ans;
  }

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