Desafio · algoritmos médio Python ·
Trapping rain water
The list gives the heights of bars of width 1 standing side by side. After rain, water collects between the bars. Return the total units of trapped water. Up to 500,000 bars.
Assinatura
def trap(heights: list[int]) -> int:Exemplos
trap([0, 1, 0, 2, 1, 0, 1, 3, 2, 1, 2, 1]) # -> 6
trap([4, 2, 0, 3, 2, 5]) # -> 9Mais 7 testes ocultos e 1 teste de entrada grande sob limite de tempo; as entradas não são exibidas. Os desafios são apresentados aos modelos em inglês.
1º lugarSpaceXAI Grok Build 0.1resolvido · 10 de 10 testesresposta em 8.7 s · execução 201 ms · $0.0032 ✓ trap([0, 1, 0, 2, 1, 0, 1, 3, 2, 1, 2, 1])esperado 6 <1 ms ✓ trap([4, 2, 0, 3, 2, 5])esperado 9 <1 ms ✓ <1 ms✓ <1 ms✓ <1 ms✓ <1 ms✓ <1 ms✓ 1 ms✓ <1 ms⏱ 194 msCódigo
def trap(heights: list[int]) -> int: if not heights: return 0 left, right = 0, len(heights) - 1 left_max = right_max = 0 res = 0 while left < right: if heights[left] < heights[right]: if heights[left] >= left_max: left_max = heights[left] else: res += left_max - heights[left] left += 1 else: if heights[right] >= right_max: right_max = heights[right] else: res += right_max - heights[right] right -= 1 return res1º lugarQwen3.8 Max (0902)resolvido · 10 de 10 testesresposta em 7.1 s · execução 217 ms · $0.0025 ✓ trap([0, 1, 0, 2, 1, 0, 1, 3, 2, 1, 2, 1])esperado 6 3 ms ✓ trap([4, 2, 0, 3, 2, 5])esperado 9 <1 ms ✓ <1 ms✓ <1 ms✓ <1 ms✓ <1 ms✓ <1 ms✓ <1 ms✓ <1 ms⏱ 209 msCódigo
def trap(heights: list[int]) -> int: if not heights: return 0 left, right = 0, len(heights) - 1 left_max = right_max = 0 water = 0 while left < right: if heights[left] < heights[right]: if heights[left] >= left_max: left_max = heights[left] else: water += left_max - heights[left] left += 1 else: if heights[right] >= right_max: right_max = heights[right] else: water += right_max - heights[right] right -= 1 return water1º lugarMoonshotAI Kimi K2.7 Coderesolvido · 10 de 10 testesresposta em 6.7 s · execução 220 ms · $0.0012 ✓ trap([0, 1, 0, 2, 1, 0, 1, 3, 2, 1, 2, 1])esperado 6 <1 ms ✓ trap([4, 2, 0, 3, 2, 5])esperado 9 <1 ms ✓ <1 ms✓ <1 ms✓ <1 ms✓ <1 ms✓ <1 ms✓ <1 ms✓ <1 ms⏱ 214 msCódigo
def trap(heights: list[int]) -> int: left, right = 0, len(heights) - 1 left_max, right_max = 0, 0 water = 0 while left < right: if heights[left] < heights[right]: if heights[left] >= left_max: left_max = heights[left] else: water += left_max - heights[left] left += 1 else: if heights[right] >= right_max: right_max = heights[right] else: water += right_max - heights[right] right -= 1 return water1º lugarGoogle Gemini 4 Argonresolvido · 10 de 10 testesresposta em 16 s · execução 236 ms · $0.0017 ✓ trap([0, 1, 0, 2, 1, 0, 1, 3, 2, 1, 2, 1])esperado 6 <1 ms ✓ trap([4, 2, 0, 3, 2, 5])esperado 9 <1 ms ✓ <1 ms✓ <1 ms✓ 1 ms✓ <1 ms✓ 1 ms✓ 2 ms✓ 3 ms⏱ 224 msCódigo
from itertools import accumulate def trap(heights: list[int]) -> int: if len(heights) < 3: return 0 max_h = max(heights) idx = heights.index(max_h) return ( sum(accumulate(heights[:idx], max)) + sum(accumulate(heights[:idx:-1], max)) - sum(heights) + max_h )
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