Tugas · algoritma sedang Python ·
Trapping rain water
The list gives the heights of bars of width 1 standing side by side. After rain, water collects between the bars. Return the total units of trapped water. Up to 500,000 bars.
Tanda tangan
def trap(heights: list[int]) -> int:Contoh
trap([0, 1, 0, 2, 1, 0, 1, 3, 2, 1, 2, 1]) # -> 6
trap([4, 2, 0, 3, 2, 5]) # -> 9Ditambah 7 pengujian tersembunyi dan 1 pengujian input besar dengan batas waktu; inputnya tidak ditampilkan. Tugas diberikan kepada model dalam bahasa Inggris.
#1SpaceXAI Grok Build 0.1selesai · 10 dari 10 pengujianrespons dalam 8.7 dtk · waktu eksekusi 201 md · $0.0032 ✓ trap([0, 1, 0, 2, 1, 0, 1, 3, 2, 1, 2, 1])diharapkan 6 <1 md ✓ trap([4, 2, 0, 3, 2, 5])diharapkan 9 <1 md ✓ <1 md✓ <1 md✓ <1 md✓ <1 md✓ <1 md✓ 1 md✓ <1 md⏱ 194 mdKode
def trap(heights: list[int]) -> int: if not heights: return 0 left, right = 0, len(heights) - 1 left_max = right_max = 0 res = 0 while left < right: if heights[left] < heights[right]: if heights[left] >= left_max: left_max = heights[left] else: res += left_max - heights[left] left += 1 else: if heights[right] >= right_max: right_max = heights[right] else: res += right_max - heights[right] right -= 1 return res#1Qwen3.8 Max (0902)selesai · 10 dari 10 pengujianrespons dalam 7.1 dtk · waktu eksekusi 217 md · $0.0025 ✓ trap([0, 1, 0, 2, 1, 0, 1, 3, 2, 1, 2, 1])diharapkan 6 3 md ✓ trap([4, 2, 0, 3, 2, 5])diharapkan 9 <1 md ✓ <1 md✓ <1 md✓ <1 md✓ <1 md✓ <1 md✓ <1 md✓ <1 md⏱ 209 mdKode
def trap(heights: list[int]) -> int: if not heights: return 0 left, right = 0, len(heights) - 1 left_max = right_max = 0 water = 0 while left < right: if heights[left] < heights[right]: if heights[left] >= left_max: left_max = heights[left] else: water += left_max - heights[left] left += 1 else: if heights[right] >= right_max: right_max = heights[right] else: water += right_max - heights[right] right -= 1 return water#1MoonshotAI Kimi K2.7 Codeselesai · 10 dari 10 pengujianrespons dalam 6.7 dtk · waktu eksekusi 220 md · $0.0012 ✓ trap([0, 1, 0, 2, 1, 0, 1, 3, 2, 1, 2, 1])diharapkan 6 <1 md ✓ trap([4, 2, 0, 3, 2, 5])diharapkan 9 <1 md ✓ <1 md✓ <1 md✓ <1 md✓ <1 md✓ <1 md✓ <1 md✓ <1 md⏱ 214 mdKode
def trap(heights: list[int]) -> int: left, right = 0, len(heights) - 1 left_max, right_max = 0, 0 water = 0 while left < right: if heights[left] < heights[right]: if heights[left] >= left_max: left_max = heights[left] else: water += left_max - heights[left] left += 1 else: if heights[right] >= right_max: right_max = heights[right] else: water += right_max - heights[right] right -= 1 return water#1Google Gemini 4 Argonselesai · 10 dari 10 pengujianrespons dalam 16 dtk · waktu eksekusi 236 md · $0.0017 ✓ trap([0, 1, 0, 2, 1, 0, 1, 3, 2, 1, 2, 1])diharapkan 6 <1 md ✓ trap([4, 2, 0, 3, 2, 5])diharapkan 9 <1 md ✓ <1 md✓ <1 md✓ 1 md✓ <1 md✓ 1 md✓ 2 md✓ 3 md⏱ 224 mdKode
from itertools import accumulate def trap(heights: list[int]) -> int: if len(heights) < 3: return 0 max_h = max(heights) idx = heights.index(max_h) return ( sum(accumulate(heights[:idx], max)) + sum(accumulate(heights[:idx:-1], max)) - sum(heights) + max_h )
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