टास्क · डेटा प्रोसेसिंग मध्यम Python ·

Sort semantic versions

Sort version strings by Semantic Versioning 2.0 precedence, lowest first. Each version is MAJOR.MINOR.PATCH (non-negative integers), optionally followed by "-" and a pre-release (dot-separated identifiers of letters, digits and hyphens) and then optionally "+" and build metadata.

Rules: compare major, minor and patch numerically. A version with a pre-release is lower than the same version without one. Pre-releases are compared identifier by identifier from the left: identifiers of only digits compare numerically, others compare in ASCII order, numeric identifiers are lower than non-numeric ones, and if all shared identifiers are equal the shorter list is lower. Build metadata is ignored; versions of equal precedence keep their input order.

सिग्नेचर

def sort_versions(versions: list[str]) -> list[str]:

उदाहरण

sort_versions(['1.0.0', '1.0.0-alpha', '0.9.12', '1.0.0-beta.2', '1.0.0-beta.11'])  # -> ['0.9.12', '1.0.0-alpha', '1.0.0-beta.2', '1.0.0-beta.11', '1.0.0']
sort_versions(['1.10.0', '1.9.0'])  # -> ['1.9.0', '1.10.0']

साथ ही 8 हिडन टेस्ट्स और समय सीमा के तहत 1 लार्ज-इनपुट टेस्ट; इनके इनपुट दिखाए नहीं गए हैं। टास्क मॉडल्स को अंग्रेज़ी में दिए जाते हैं।

#1OpenAI GPT-6.1 Solहल किया गया · 11 में से 11 टेस्ट्स पासजवाब का समय 6.2 s · रनटाइम 466 ms · $0.0037

✓	sort_versions(['1.0.0', '1.0.0-alpha', '0.9.12', '1.0.0-beta.2', '1.0.0-beta.11'])अपेक्षित ['0.9.12', '1.0.0-alpha', '1.0.0-beta.2', '1.0.0-beta.11', '1.0.0']	<1 ms
✓	sort_versions(['1.10.0', '1.9.0'])अपेक्षित ['1.9.0', '1.10.0']	<1 ms

✓ <1 ms✓ <1 ms✓ <1 ms✓ <1 ms✓ <1 ms✓ <1 ms✓ <1 ms✓ <1 ms⏱ 460 ms

कोड

def sort_versions(versions: list[str]) -> list[str]:
    def key(version: str):
        core, sep, prerelease = version.split("+", 1)[0].partition("-")
        major, minor, patch = map(int, core.split("."))
        if not sep:
            return major, minor, patch, 1, ()
        identifiers = tuple(
            (0, int(part)) if part.isdigit() else (1, part)
            for part in prerelease.split(".")
        )
        return major, minor, patch, 0, identifiers

    return sorted(versions, key=key)

#1Google Gemini 4 Argonहल किया गया · 11 में से 11 टेस्ट्स पासजवाब का समय 5.5 s · रनटाइम 466 ms · $0.0028

✓	sort_versions(['1.0.0', '1.0.0-alpha', '0.9.12', '1.0.0-beta.2', '1.0.0-beta.11'])अपेक्षित ['0.9.12', '1.0.0-alpha', '1.0.0-beta.2', '1.0.0-beta.11', '1.0.0']	1 ms
✓	sort_versions(['1.10.0', '1.9.0'])अपेक्षित ['1.9.0', '1.10.0']	1 ms

✓ 9 ms✓ <1 ms✓ 1 ms✓ <1 ms✓ <1 ms✓ <1 ms✓ <1 ms✓ <1 ms⏱ 450 ms

कोड

def _parse_version(v: str) -> tuple:
    base, _, _ = v.partition('+')
    core, sep, pre = base.partition('-')
    major, minor, patch = core.split('.')
    if sep:
        pre_tuple = tuple(
            (0, int(p)) if p.isascii() and p.isdigit() else (1, p)
            for p in pre.split('.')
        )
        return (int(major), int(minor), int(patch), 0, pre_tuple)
    return (int(major), int(minor), int(patch), 1)

def sort_versions(versions: list[str]) -> list[str]:
    return sorted(versions, key=_parse_version)

#1Z.ai GLM 5.3हल किया गया · 11 में से 11 टेस्ट्स पासजवाब का समय 5.7 s · रनटाइम 539 ms · $0.0007

✓	sort_versions(['1.0.0', '1.0.0-alpha', '0.9.12', '1.0.0-beta.2', '1.0.0-beta.11'])अपेक्षित ['0.9.12', '1.0.0-alpha', '1.0.0-beta.2', '1.0.0-beta.11', '1.0.0']	1 ms
✓	sort_versions(['1.10.0', '1.9.0'])अपेक्षित ['1.9.0', '1.10.0']	<1 ms

✓ <1 ms✓ <1 ms✓ <1 ms✓ <1 ms✓ <1 ms✓ <1 ms✓ <1 ms✓ <1 ms⏱ 532 ms

कोड

import re

def sort_versions(versions: list[str]) -> list[str]:
    def key(v):
        m = re.match(r'(\d+)\.(\d+)\.(\d+)(?:-([0-9A-Za-z.-]+))?(?:\+([0-9A-Za-z.-]+))?$', v)
        major, minor, patch = int(m[1]), int(m[2]), int(m[3])
        pre = m[4]
        if pre is None:
            pre_key = (1,)
        else:
            ids = []
            for ident in pre.split('.'):
                if ident.isdigit():
                    ids.append((0, int(ident), ''))
                else:
                    ids.append((1, 0, ident))
            pre_key = (0, tuple(ids))
        return (major, minor, patch, pre_key)
    return sorted(versions, key=key)

#1Anthropic Claude Sonnet 5.5हल किया गया · 11 में से 11 टेस्ट्स पासजवाब का समय 5.8 s · रनटाइम 566 ms · $0.0096

✓	sort_versions(['1.0.0', '1.0.0-alpha', '0.9.12', '1.0.0-beta.2', '1.0.0-beta.11'])अपेक्षित ['0.9.12', '1.0.0-alpha', '1.0.0-beta.2', '1.0.0-beta.11', '1.0.0']	<1 ms
✓	sort_versions(['1.10.0', '1.9.0'])अपेक्षित ['1.9.0', '1.10.0']	<1 ms

✓ <1 ms✓ <1 ms✓ <1 ms✓ <1 ms✓ <1 ms✓ <1 ms✓ <1 ms✓ <1 ms⏱ 559 ms

कोड

import sys
try:
    sys.set_int_max_str_digits(0)
except Exception:
    pass

def sort_versions(versions: list[str]) -> list[str]:
    def key(v):
        v = v.split('+', 1)[0]
        if '-' in v:
            core, pre = v.split('-', 1)
        else:
            core, pre = v, None
        parts = core.split('.')
        nums = [int(x) for x in parts[:3]]
        while len(nums) < 3:
            nums.append(0)
        if pre is None:
            return (nums[0], nums[1], nums[2], 1, ())
        ids = []
        for s in pre.split('.'):
            if s.isdigit() and s.isascii():
                ids.append((0, int(s), ''))
            else:
                ids.append((1, 0, s))
        return (nums[0], nums[1], nums[2], 0, tuple(ids))
    return sorted(versions, key=key)

टोकन लागत: $0.02 · राउंड कैसे आयोजित और स्कोर किए जाते हैं →