Tugas · string sulit JavaScript ·

Count distinct substrings

/**
 * @param {string} s
 * @returns {number}
 */
function count_distinct_substrings(s)

count_distinct_substrings("abab")  // -> 7
count_distinct_substrings("aaa")  // -> 3
count_distinct_substrings("")  // -> 0

• #1MiniMax M3.1 Flashselesai · 14 dari 14 pengujianrespons dalam 5.8 dtk · waktu eksekusi 388 md · $0.0009

  ✓	count_distinct_substrings("abab")diharapkan 7	2 md
  ✓	count_distinct_substrings("aaa")diharapkan 3	<1 md
  ✓	count_distinct_substrings("")diharapkan 0	1 md

  ✓ 1 md✓ <1 md✓ <1 md✓ <1 md✓ 2 md✓ 28 md✓ 1 md✓ <1 md⏱ 292 md⏱ 22 md⏱ 35 md
  Kode

  function count_distinct_substrings(s) {
    const n = s.length;
    if (n === 0) return 0;
  
    const maxStates = 2 * n + 1;
    const tr = new Int32Array(maxStates * 26);
    const len = new Int32Array(maxStates);
    const link = new Int32Array(maxStates);
  
    link[0] = -1;
    let size = 1;
    let last = 0;
  
    for (let i = 0; i < n; i++) {
      const c = s.charCodeAt(i) - 97;
      const cur = size++;
      len[cur] = len[last] + 1;
  
      let p = last;
      while (p !== -1) {
        const idx = p * 26 + c;
        if (tr[idx] !== 0) break;
        tr[idx] = cur;
        p = link[p];
      }
  
      if (p === -1) {
        link[cur] = 0;
      } else {
        const q = tr[p * 26 + c];
        if (len[p] + 1 === len[q]) {
          link[cur] = q;
        } else {
          const clone = size++;
          len[clone] = len[p] + 1;
          link[clone] = link[q];
          const cb = clone * 26, qb = q * 26;
          for (let k = 0; k < 26; k++) tr[cb + k] = tr[qb + k];
          while (p !== -1) {
            const idx = p * 26 + c;
            if (tr[idx] !== q) break;
            tr[idx] = clone;
            p = link[p];
          }
          link[q] = clone;
          link[cur] = clone;
        }
      }
      last = cur;
    }
  
    let total = 0;
    for (let v = 1; v < size; v++) total += len[v] - len[link[v]];
    return total;
  }

• #2Google Gemini 3.8 Flashselesai · 14 dari 14 pengujianrespons dalam 6.4 dtk · waktu eksekusi 487 md · $0.0026

  ✓	count_distinct_substrings("abab")diharapkan 7	6 md
  ✓	count_distinct_substrings("aaa")diharapkan 3	1 md
  ✓	count_distinct_substrings("")diharapkan 0	1 md

  ✓ <1 md✓ 1 md✓ 1 md✓ 17 md✓ 2 md✓ 1 md✓ 1 md✓ <1 md⏱ 330 md⏱ 99 md⏱ 25 md
  Kode

  /**
   * @param {string} s
   * @returns {number}
   */
  function count_distinct_substrings(s) {
      const n = s.length;
      if (n === 0) return 0;
      if (n === 1) return 1;
  
      // Suffix Automaton (SAM) approach
      // Max states: 2 * n
      const maxStates = 2 * n;
      const link = new Int32Array(maxStates);
      const len = new Int32Array(maxStates);
      // 26 transitions per state
      const nextState = new Int32Array(maxStates * 26);
      nextState.fill(-1);
  
      link[0] = -1;
      len[0] = 0;
      let sz = 1;
      let last = 0;
  
      for (let i = 0; i < n; i++) {
          const c = s.charCodeAt(i) - 97;
          const cur = sz++;
          len[cur] = len[last] + 1;
  
          let p = last;
          while (p !== -1 && nextState[p * 26 + c] === -1) {
              nextState[p * 26 + c] = cur;
              p = link[p];
          }
  
          if (p === -1) {
              link[cur] = 0;
          } else {
              const q = nextState[p * 26 + c];
              if (len[p] + 1 === len[q]) {
                  link[cur] = q;
              } else {
                  const clone = sz++;
                  len[clone] = len[p] + 1;
                  link[clone] = link[q];
                  // copy transitions
                  const qOffset = q * 26;
                  const cloneOffset = clone * 26;
                  for (let k = 0; k < 26; k++) {
                      nextState[cloneOffset + k] = nextState[qOffset + k];
                  }
  
                  while (p !== -1 && nextState[p * 26 + c] === q) {
                      nextState[p * 26 + c] = clone;
                      p = link[p];
                  }
                  link[q] = clone;
                  link[cur] = clone;
              }
          }
          last = cur;
      }
  
      let ans = 0;
      for (let i = 1; i < sz; i++) {
          ans += len[i] - len[link[i]];
      }
  
      return ans;
  }

• #3Qwen3.8 Max (0902)selesai · 14 dari 14 pengujianrespons dalam 33 dtk · waktu eksekusi 952 md · $0.01

  ✓	count_distinct_substrings("abab")diharapkan 7	2 md
  ✓	count_distinct_substrings("aaa")diharapkan 3	1 md
  ✓	count_distinct_substrings("")diharapkan 0	1 md

  ✓ <1 md✓ 1 md✓ 27 md✓ 1 md✓ <1 md✓ 1 md✓ 1 md✓ <1 md⏱ 435 md⏱ 361 md⏱ 117 md
  Kode

  function count_distinct_substrings(s) {
      const n = s.length;
      if (n === 0) return 0;
      
      // Build suffix array using prefix doubling
      let sa = new Array(n);
      let rank = new Array(n);
      let tmp = new Array(n);
      
      for (let i = 0; i < n; i++) {
          sa[i] = i;
          rank[i] = s.charCodeAt(i);
      }
      
      for (let k = 1; k < n; k <<= 1) {
          const r = rank; // capture current rank
          const cmp = (a, b) => {
              if (r[a] !== r[b]) return r[a] - r[b];
              const ra = a + k < n ? r[a + k] : -1;
              const rb = b + k < n ? r[b + k] : -1;
              return ra - rb;
          };
          sa.sort(cmp);
          
          tmp[sa[0]] = 0;
          for (let i = 1; i < n; i++) {
              tmp[sa[i]] = tmp[sa[i-1]] + (cmp(sa[i-1], sa[i]) < 0 ? 1 : 0);
          }
          [rank, tmp] = [tmp, rank];
          
          if (rank[sa[n-1]] === n - 1) break;
      }
      
      // Kasai's algorithm for LCP array
      // rank[i] = position of suffix i in suffix array
      let lcpSum = 0;
      let h = 0;
      
      for (let i = 0; i < n; i++) {
          if (rank[i] > 0) {
              let j = sa[rank[i] - 1];
              while (i + h < n && j + h < n && s.charCodeAt(i + h) === s.charCodeAt(j + h)) h++;
              lcpSum += h;
              if (h > 0) h--;
          } else {
              h = 0;
          }
      }
      
      return n * (n + 1) / 2 - lcpSum;
  }

• #4SpaceXAI Grok Build 0.1tidak selesai · 11 dari 14 pengujianrespons dalam 37 dtk · waktu eksekusi 1.9 dtk · $0.02

  ✓	count_distinct_substrings("abab")diharapkan 7	2 md
  ✓	count_distinct_substrings("aaa")diharapkan 3	1 md
  ✓	count_distinct_substrings("")diharapkan 0	22 md

  ✓ 2 md✓ 1 md✓ 3 md✓ 1 md✓ <1 md✓ 2 md✓ 2 md✓ 1 md⏱ batas waktu terlampaui⏱ batas waktu terlampaui⏱ batas waktu terlampaui
  Kode

  function count_distinct_substrings(s) {
    const n = s.length;
    if (n === 0) return 0;
    const MAX = 2 * n + 10;
    const len = new Array(MAX);
    const link = new Array(MAX);
    const trans = new Array(MAX);
    for (let i = 0; i < MAX; i++) {
      trans[i] = new Array(26).fill(-1);
    }
    let tot = 1;
    len[0] = 0;
    link[0] = -1;
    let last = 0;
    for (let i = 0; i < n; i++) {
      const c = s.charCodeAt(i) - 97;
      let cur = tot++;
      len[cur] = len[last] + 1;
      let p = last;
      while (p !== -1 && trans[p][c] === -1) {
        trans[p][c] = cur;
        p = link[p];
      }
      if (p === -1) {
        link[cur] = 0;
      } else {
        let q = trans[p][c];
        if (len[q] === len[p] + 1) {
          link[cur] = q;
        } else {
          let clone = tot++;
          len[clone] = len[p] + 1;
          link[clone] = link[q];
          for (let j = 0; j < 26; j++) {
            trans[clone][j] = trans[q][j];
          }
          while (p !== -1 && trans[p][c] === q) {
            trans[p][c] = clone;
            p = link[p];
          }
          link[q] = clone;
          link[cur] = clone;
        }
      }
      last = cur;
    }
    let count = 0;
    for (let i = 1; i < tot; i++) {
      count += len[i] - len[link[i]];
    }
    return count;
  }

  Percobaan kedua

  selesai · 14 dari 14 pengujianrespons dalam 27 dtk · $0.01

  Model melihat berapa banyak tes yang gagal, contoh yang gagal beserta nilai yang diharapkan dan yang dihasilkan, serta hanya alasan mengapa tes tersembunyi gagal, bukan inputnya. Tidak memengaruhi peringkat atau rating.

  ✓	count_distinct_substrings("abab")diharapkan 7	2 md
  ✓	count_distinct_substrings("aaa")diharapkan 3	<1 md
  ✓	count_distinct_substrings("")diharapkan 0	<1 md

  ✓ 1 md✓ 2 md✓ 1 md✓ <1 md✓ <1 md✓ <1 md✓ <1 md✓ 1 md⏱ 250 md⏱ 46 md⏱ 117 md

  Kode

  function count_distinct_substrings(s) {
    const n = s.length;
    if (n === 0) return 0;
    const MAX = 2 * n + 5;
    const len = new Int32Array(MAX);
    const link = new Int32Array(MAX);
    const trans = new Int32Array(MAX * 26);
    trans.fill(-1);
    let tot = 1;
    len[0] = 0;
    link[0] = -1;
    let last = 0;
    for (let i = 0; i < n; i++) {
      const c = s.charCodeAt(i) - 97;
      let cur = tot++;
      len[cur] = len[last] + 1;
      let p = last;
      while (p !== -1 && trans[p * 26 + c] === -1) {
        trans[p * 26 + c] = cur;
        p = link[p];
      }
      if (p === -1) {
        link[cur] = 0;
      } else {
        let q = trans[p * 26 + c];
        if (len[q] === len[p] + 1) {
          link[cur] = q;
        } else {
          let clone = tot++;
          len[clone] = len[p] + 1;
          link[clone] = link[q];
          const qbase = q * 26;
          const clonebase = clone * 26;
          for (let j = 0; j < 26; j++) {
            trans[clonebase + j] = trans[qbase + j];
          }
          while (p !== -1 && trans[p * 26 + c] === q) {
            trans[p * 26 + c] = clone;
            p = link[p];
          }
          link[q] = clone;
          link[cur] = clone;
        }
      }
      last = cur;
    }
    let count = 0;
    for (let i = 1; i < tot; i++) {
      count += len[i] - len[link[i]];
    }
    return count;
  }

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